nttlTraits Method - IsOdd

Description

For a given value, x, return true if x is odd, and false if x is even.

One typical way of calculating this is to use x % 2. This involves a division operation, which is intrinsically slow. A better way to calculate this is to use x & 1. Even this is slower than it needs to be. For a multiple precision integer, only the least significant digit needs to be used.

The default implementation of this method uses x & 1. If the type T does not implement operator&, then this method will have to be specialized for T.

Signature: template<class T> bool nttlTraits::IsOdd( const T& x )

Parameters

Name	Type	Description
x	T	Some number.

Returns: ( bool ) true if x is odd; false otherwise.

Example

#include <nttl/nttlTraits.h>
...
nttlTraits<int> tr;
...
int x = 123;
if( tr.IsOdd( x ) )
    ...